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-   -   Pentium 4 bounds over the 3Ghrz limit! (alliedassault.us/showthread.php?t=14450)

Bazooka_Joe 12-09-2002 11:37 AM

Pentium 4 bounds over the 3Ghrz limit!
 
A little late, but yes, the P4 now comes in 3.06Ghrz chips! (Time to update Rudedog! lol)

You can own one (not 0wn) for as low as $700 bucks! ed: (http://www.pricewatch.com).

Zoner 12-09-2002 12:23 PM

*Zone pisses on his P3 550MHz*

cry:


Zone

Bazooka_Joe 12-09-2002 12:27 PM

heh

When u gonna update d00d?

pest 12-09-2002 12:27 PM

Did you know that you could buy an AMD XP2100 for the same price as a PIII 850? ed: oOo:

Webb 12-09-2002 01:34 PM

Still happy with my P4 1.5Ghz oOo:

Star85 12-09-2002 07:49 PM

I like my P4 2.0 Ghz

Old Reliable 12-09-2002 07:57 PM

866 p3 i need to upgrade but computers are so expensive...

redsoccerdevil 12-09-2002 09:59 PM

The [H] got that mother up to 3.6 something Ghz. Holy Balls! 18,000 something 3D marks. (pisses on 4,100 system)
-Red

12-09-2002 10:09 PM

cool in a few years there may be a game that needs that.

Arkan 12-09-2002 10:49 PM

I'll stick to the AMD XP's....thank you very much !!

intrestedviewer 12-09-2002 11:23 PM

i wish i had that kinda cash cry: buying that thing is just a wast of money though. Nothing needs that much processor, yet.

ninty 12-09-2002 11:27 PM

Quote:

Originally Posted by intrestedviewer
i wish i had that kinda cash cry: buying that thing is just a wast of money though. Nothing needs that much processor, yet.

Well if you want to say, get a vector or matrix some calculations would need this much processor if the question is large.

There are some questions that computers cannot figure out because it takes way too long. Years and years even with todays computers. But for the average person, your right, we don't need it.

Innoxx 12-09-2002 11:31 PM

Yeah, I'd rather spend 700 dollars (roughy 1200 dollars CDN) on booze and pussy.

ninty 12-09-2002 11:33 PM

$1200/$5 = 240 pussies. Thats a lot of pussies.

vVolf 12-10-2002 03:13 AM

More like $1200/$25 = 48. $5 won't get you Pu$$-ay.


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